What is the current in a circuit with a 30 A/50 mV shunt and a voltage drop of 10 mV?

What is the current in a circuit with a 30 A/50 mV shunt and a voltage drop of 10 mV?

• A. 1.2 A
• B. 6 A
• C. 8 A
• D. 12 A

Answer: (B)

To determine the current flowing in the circuit given the specifications of a 30 A/50 mV shunt and a voltage drop of 10 mV, we begin by analyzing the relationship between voltage, current, and resistance as outlined by Ohm's Law. The shunt is rated to allow a maximum of 30 A to produce a voltage drop of 50 mV across it. This establishes a proportional relationship between current and voltage drop according to the following formula: \[ \text{Current} (I) = \left(\frac{\text{Voltage drop across the shunt}}{\text{Voltage per Amp}} \right) \] Here, the voltage per amp can be derived from the shunt rating: \[ \text{Voltage per Amp} = \frac{50 \text{ mV}}{30 \text{ A}} = \frac{50 \times 10^{-3} \text{ V}}{30} = 1.6667 \text{ mV/A} \] Next, to find the current corresponding to a 10 mV drop: \[ I = \frac{10 \text{ mV}}{1.6667 \text{ mV/A}}

To determine the current flowing in the circuit given the specifications of a 30 A/50 mV shunt and a voltage drop of 10 mV, we begin by analyzing the relationship between voltage, current, and resistance as outlined by Ohm's Law.

The shunt is rated to allow a maximum of 30 A to produce a voltage drop of 50 mV across it. This establishes a proportional relationship between current and voltage drop according to the following formula:

[

\text{Current} (I) = \left(\frac{\text{Voltage drop across the shunt}}{\text{Voltage per Amp}} \right)

]

Here, the voltage per amp can be derived from the shunt rating:

[

\text{Voltage per Amp} = \frac{50 \text{ mV}}{30 \text{ A}} = \frac{50 \times 10^{-3} \text{ V}}{30} = 1.6667 \text{ mV/A}

]

Next, to find the current corresponding to a 10 mV drop:

[

I = \frac{10 \text{ mV}}{1.6667 \text{ mV/A}}